Question Number 87861 by Rio Michael last updated on 06/Apr/20

Commented by MJS last updated on 06/Apr/20
![tanh 2x =((e^(4x) −1)/(e^(4x) +1)) ∫tanh 2x dx= [t=e^(4x) → dx=(dt/(4e^(4x) ))] =(1/4)∫((t−1)/(t(t+1)))dt=(1/2)∫(dt/(t+1))−(1/4)∫(dt/t)= =(1/2)ln (t+1) −(1/4)ln t =−x+(1/2)ln (e^(4x) +1) +C](https://www.tinkutara.com/question/Q87868.png)
Commented by Rio Michael last updated on 06/Apr/20

Commented by MJS last updated on 07/Apr/20

Commented by Rio Michael last updated on 07/Apr/20
