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0-pi-e-cos-x-e-cos-x-e-cos-x-dx-




Question Number 151345 by peter frank last updated on 20/Aug/21
∫_0 ^π (e^(cos x) /(e^(cos x) +e^(−cos x) ))dx
0πecosxecosx+ecosxdx
Answered by Olaf_Thorendsen last updated on 20/Aug/21
I = ∫_0 ^π (e^(cosx) /(e^(cosx) +e^(−cosx) )) dx   (1)  Let u = π−x :  I = ∫_0 ^π (e^(−cosu) /(e^(−cosu) +e^(cosu) )) du   (2)  (((1)+(2))/2) : I = (π/2)
I=0πecosxecosx+ecosxdx(1)Letu=πx:I=0πecosuecosu+ecosudu(2)(1)+(2)2:I=π2

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