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0-pi-e-x-2-dx-




Question Number 127106 by mohammad17 last updated on 26/Dec/20
∫_0 ^( π) e^(−x^2 ) dx
0πex2dx
Commented by Dwaipayan Shikari last updated on 27/Dec/20
((√π)/2)−(e^(−π^2 ) /(2π+(1/(π+(2/(2π+(3/(π+(4/(....))))))))))
π2eπ22π+1π+22π+3π+4.

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