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1-0-5-x-5-x-dx-




Question Number 186051 by Tom last updated on 31/Jan/23
∫_(−1) ^0 ∣5^x −5^(−x) ∣dx
015x5xdx
Answered by Frix last updated on 31/Jan/23
=∫_(−1) ^0 ∣2sinh (xln 5)∣dx=  =−2∫_(−1) ^0 sinh (xln 5) dx=  =−(2/(ln 5))[cosh (xln 5)]_(−1) ^0 =((16)/(5ln 5))
=012sinh(xln5)dx==201sinh(xln5)dx==2ln5[cosh(xln5)]10=165ln5

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