1-1-1-y-2-1-y-2-ln-x-2-y-2-1-dx-dy- Tinku Tara June 4, 2023 Integration 0 Comments FacebookTweetPin Question Number 190419 by horsebrand11 last updated on 02/Apr/23 ∫1−1∫1−y2−1−y2ln(x2+y2+1)dxdy=? Answered by witcher3 last updated on 04/Apr/23 x=rcos(a)y=rsin(a)−1⩽rsin(a)⩽1,⇒a∈[−π2,π2]∣x∣⩽1−y2⇔0⩽x2+y2⩽1⇔0⩽r⩽1−1r⩽sin(a)⩽1r∫01∫−π2π2rln(1+r2)dadr=π2∫01ln(1+r2)dr2=π2∫01ln(1+x)dx=π2.(2ln(2)−1) Terms of Service Privacy Policy Contact: info@tinkutara.com FacebookTweetPin Post navigation Previous Previous post: e-x-1-sin-x-1-cos-x-dx-Next Next post: Question-59346 Leave a Reply Cancel replyYour email address will not be published. Required fields are marked *Comment * Name * Save my name, email, and website in this browser for the next time I comment.