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1-1-16-1-81-1-256-




Question Number 99994 by Dwaipayan Shikari last updated on 24/Jun/20
1+(1/(16))+(1/(81))+(1/(256))+.....∞
$$\mathrm{1}+\frac{\mathrm{1}}{\mathrm{16}}+\frac{\mathrm{1}}{\mathrm{81}}+\frac{\mathrm{1}}{\mathrm{256}}+…..\infty \\ $$
Answered by smridha last updated on 24/Jun/20
𝛇(4)=(𝛑^4 /(90))
$$\boldsymbol{\zeta}\left(\mathrm{4}\right)=\frac{\boldsymbol{\pi}^{\mathrm{4}} }{\mathrm{90}} \\ $$

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