1-1-2-1-3-1-5-find-the-sum-of-the-series-

Question Number 34504 by NECx last updated on 07/May/18

1 - \frac{1}{2} + \frac{1}{3} - \frac{1}{5} + \dots .

f i n d t h e s u m o f t h e s e r i e s

Commented by abdo mathsup 649 cc last updated on 07/May/18

t h e q u e s t i o n i s n o t c l e a r s i r N e c x \dots

Answered by tanmay.chaudhury50@gmail.com last updated on 07/May/18

l o g (1 + t) = t - \frac{t^{2}}{2} + \frac{t^{3}}{3} - \frac{t^{4}}{4} \dots .

l o g (1 - t) = - t - \frac{t^{2}}{2} - \frac{t^{3}}{3} - \frac{t^{4}}{4} \dots

l o g 2 = 1 - \frac{1}{2} + \frac{1}{3} - \frac{1}{4} \dots

p u t t = i

l o g (1 + i) = i - \frac{i^{2}}{2} + \frac{i^{3}}{3} - \frac{i^{4}}{4} + \frac{i^{5}}{5} \dots

p l s r e c h e c k t h e p r o b e m p l s