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Question Number 189559 by 073 last updated on 18/Mar/23
 (−1)^(1/3) =?  ((−1))^(1/3) =?
(1)13=?13=?
Answered by Frix last updated on 18/Mar/23
−1=e^(iπ)   ⇒  (−1)^(1/n) =e^(i(π/n)) =cos (π/n) +i sin (π/n)  (−1)^(1/2) =e^(i(π/2)) =cos (π/2) +i sin (π/2) =i  (−1)^(1/3) =cos (π/3) +i sin (π/3) =(1/2)+((√3)/2)i
1=eiπ(1)1n=eiπn=cosπn+isinπn(1)12=eiπ2=cosπ2+isinπ2=i(1)13=cosπ3+isinπ3=12+32i

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