1-1-log-x-2-dx-

Question Number 44639 by arvinddayama01@gmail.com last updated on 02/Oct/18

\int \frac{1}{1 + {(\log x)}^{2}} dx = ?

Commented by tanmay.chaudhury50@gmail.com last updated on 02/Oct/18

t = l n x x = e^{t} d x = e^{t} d t

\int \frac{e^{t} d t}{1 + t^{2}} i s i t i n t r e g a b l e \dots