1-1-x-x-1-1-1-2019-2019-Find-all-possible-values-of-x-

Question Number 93241 by Ayod 19 last updated on 12/May/20

{(1 + \frac{1}{x})}^{x + 1} = {(1 + \frac{1}{2019})}^{2019}

Find all possible values of x

Answered by prakash jain last updated on 12/May/20

x = - 2020

{(1 - \frac{1}{2020})}^{- 2019}

= {(\frac{2019}{2020})}^{- 2019} = {(\frac{2020}{2019})}^{2019} = {(1 + \frac{1}{2019})}^{2019}

only one solution

You can prove no other solution using

inequalities