Question Number 36227 by Cheyboy last updated on 30/May/18
$$\mathrm{1}×\mathrm{10}^{\mathrm{7}\:} {electrons}\:{pass}\:{through}\:{a}\: \\ $$$${conductor}\:{in}\:\mathrm{1}.\mathrm{0}\mu{s}.{Find}\:{the}\: \\ $$$${current}\:{in}\:{Amperes}\:{flowing} \\ $$$${through}\:{the}\:{conductor}. \\ $$$${electronic}\:{charge}=\mathrm{1}.\mathrm{6}×\mathrm{10}^{−\mathrm{19}} {C} \\ $$
Answered by tanmay.chaudhury50@gmail.com last updated on 30/May/18
$${i}=\frac{{ne}}{{t}}=\frac{\mathrm{1}×\mathrm{10}^{\mathrm{7}} ×\mathrm{1}.\mathrm{6}×\mathrm{10}^{−\mathrm{19}} }{\mathrm{1}×\mathrm{10}^{−\mathrm{6}} }\:{amp} \\ $$
Commented by Cheyboy last updated on 30/May/18
$${Thank}\:{u}\:{sir}\: \\ $$