Question Number 84036 by M±th+et£s last updated on 08/Mar/20
$$\int_{−\mathrm{1}} ^{\mathrm{10}} {sin}\left({x}−\mid{x}\mid\right)\:{dx} \\ $$
Answered by TANMAY PANACEA last updated on 09/Mar/20
$$\int_{−\mathrm{1}} ^{\mathrm{0}} {sin}\left({x}+{x}\right){dx}+\int_{\mathrm{0}} ^{\mathrm{10}} {sin}\left({x}−{x}\right){dx} \\ $$$$=\frac{−\mid{cos}\mathrm{2}{x}\mid_{−\mathrm{1}} ^{\mathrm{0}} }{\mathrm{2}}+\mathrm{0} \\ $$$$=\frac{−\mathrm{1}}{\mathrm{2}}\left\{\left({cos}\mathrm{0}−{cos}\left(−\mathrm{2}\right)\right\}=\frac{{cos}\left(−\mathrm{2}\right)−\mathrm{1}}{\mathrm{2}}=\frac{−\mathrm{1}+{cos}\mathrm{2}}{\mathrm{2}}\right. \\ $$
Commented by M±th+et£s last updated on 09/Mar/20
$${thaks}\:{sir}\:{nice}\:{solution}\: \\ $$
Commented by TANMAY PANACEA last updated on 09/Mar/20
$${most}\:{welcomesir} \\ $$