1-10-x-d-x-x-

Question Number 159693 by mnjuly1970 last updated on 20/Nov/21

Ω := \int_{1}^{10} x d (x + ⌊ x ⌋) = ?

Answered by mr W last updated on 20/Nov/21

Ω = \int_{1}^{10} x d (x + ⌊ x ⌋)

= \int_{1}^{10} x d x

= \frac{10^{2} - 1^{2}}{2} = \frac{99}{2}

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