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Question Number 90282 by 20000193 last updated on 22/Apr/20
(1/(2α+β))+(1/(α+2β))
$$\frac{\mathrm{1}}{\mathrm{2}\alpha+\beta}+\frac{\mathrm{1}}{\alpha+\mathrm{2}\beta} \\ $$
Commented by jagoll last updated on 22/Apr/20
((α+2β+2α+β)/((2α+β)(α+2β))) = ((3α+3β)/(2α^2 +5αβ+2β^2 ))
$$\frac{\alpha+\mathrm{2}\beta+\mathrm{2}\alpha+\beta}{\left(\mathrm{2}\alpha+\beta\right)\left(\alpha+\mathrm{2}\beta\right)}\:=\:\frac{\mathrm{3}\alpha+\mathrm{3}\beta}{\mathrm{2}\alpha^{\mathrm{2}} +\mathrm{5}\alpha\beta+\mathrm{2}\beta^{\mathrm{2}} } \\ $$

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