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1-2-1-3-1-9-9-1-8-2-1-9-




Question Number 148350 by Fikret last updated on 27/Jul/21
(((1/2)+(1/3)+....+(1/9))/((9/1)+(8/2)+...+(1/9)))=?
$$\frac{\frac{\mathrm{1}}{\mathrm{2}}+\frac{\mathrm{1}}{\mathrm{3}}+….+\frac{\mathrm{1}}{\mathrm{9}}}{\frac{\mathrm{9}}{\mathrm{1}}+\frac{\mathrm{8}}{\mathrm{2}}+…+\frac{\mathrm{1}}{\mathrm{9}}}=? \\ $$
Commented by liberty last updated on 27/Jul/21
= ((4609)/(48610))
$$=\:\frac{\mathrm{4609}}{\mathrm{48610}} \\ $$

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