Question Number 127078 by amns last updated on 26/Dec/20
$$\frac{\frac{\frac{\mathrm{1}}{\mathrm{2}}}{\:\sqrt{\mathrm{2}}}}{\frac{\frac{\frac{\mathrm{1}\:+\:\frac{\mathrm{1}}{\:\sqrt{\mathrm{2}}}}{\mathrm{10}}}{\mathrm{3}}}{\mathrm{2}}}\:=\:? \\ $$
Commented by hknkrc46 last updated on 26/Dec/20
$$\left(\frac{\mathrm{1}}{\mathrm{2}}\::\:\sqrt{\mathrm{2}}\right)\::\:\left[\left(\mathrm{1}\:+\:\frac{\mathrm{1}}{\:\sqrt{\mathrm{2}}}\right)\::\:\mathrm{10}\::\:\mathrm{3}\::\:\mathrm{2}\right] \\ $$$$=\:\left(\frac{\mathrm{1}}{\mathrm{2}}\:\centerdot\:\frac{\mathrm{1}}{\:\sqrt{\mathrm{2}}}\right)\::\:\left[\frac{\sqrt{\mathrm{2}}\:+\:\mathrm{1}}{\:\sqrt{\mathrm{2}}}\:\centerdot\:\frac{\mathrm{1}}{\mathrm{10}}\:\centerdot\:\frac{\mathrm{1}}{\mathrm{3}}\:\centerdot\:\frac{\mathrm{1}}{\mathrm{2}}\right] \\ $$$$=\:\frac{\mathrm{1}}{\mathrm{2}}\:\centerdot\:\frac{\mathrm{1}}{\:\sqrt{\mathrm{2}}}\:\centerdot\:\frac{\sqrt{\mathrm{2}}}{\:\sqrt{\mathrm{2}}\:+\:\mathrm{1}}\:\centerdot\:\frac{\mathrm{10}}{\mathrm{1}}\:\centerdot\:\frac{\mathrm{3}}{\mathrm{1}}\:\centerdot\:\frac{\mathrm{2}}{\mathrm{1}} \\ $$$$=\:\frac{\mathrm{30}}{\:\sqrt{\mathrm{2}}\:+\:\mathrm{1}}\:=\:\frac{\mathrm{30}\left(\sqrt{\mathrm{2}}\:−\:\mathrm{1}\right)}{\left(\sqrt{\mathrm{2}}\:+\:\mathrm{1}\right)\left(\sqrt{\mathrm{2}}\:−\:\mathrm{1}\right)} \\ $$$$=\:\mathrm{30}\sqrt{\mathrm{2}}\:−\:\mathrm{30} \\ $$