1-2-log-3-25-1-2-log-5-9-

Question Number 146895 by mathdanisur last updated on 16/Jul/21

\frac{1}{2 + {l o g}_{3} (25)} + \frac{1}{2 + {l o g}_{5} (9)} = ?

Answered by EDWIN88 last updated on 16/Jul/21

\Rightarrow L = \frac{1}{2 + \log_{3} (25)} + \frac{1}{2 + \log_{5} (9)}

\Rightarrow L = \frac{1}{\log_{3} (9 \times 25)} + \frac{1}{\log_{5} (9 \times 25)}

\Rightarrow L = \log_{225} (3) + \log_{225} (5)

\Rightarrow L = \log_{225} (15) = \frac{1}{2}

Commented by mathdanisur last updated on 16/Jul/21

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