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Question Number 117828 by redouaneee last updated on 13/Oct/20
1)((√3)−1)((√3)+1)=(√3)×(√3)−(√3)−1  =3−(√3)−1  =2−(√3)  2)(2x+(√3))(2x−(√3))=(2x)^2 −2x(√3)+2x(√3)−3  =4x^2 −3
$$\left.\mathrm{1}\right)\left(\sqrt{\mathrm{3}}−\mathrm{1}\right)\left(\sqrt{\mathrm{3}}+\mathrm{1}\right)=\sqrt{\mathrm{3}}×\sqrt{\mathrm{3}}−\sqrt{\mathrm{3}}−\mathrm{1} \\ $$$$=\mathrm{3}−\sqrt{\mathrm{3}}−\mathrm{1} \\ $$$$=\mathrm{2}−\sqrt{\mathrm{3}} \\ $$$$\left.\mathrm{2}\right)\left(\mathrm{2}{x}+\sqrt{\mathrm{3}}\right)\left(\mathrm{2}{x}−\sqrt{\mathrm{3}}\right)=\left(\mathrm{2}{x}\right)^{\mathrm{2}} −\mathrm{2}{x}\sqrt{\mathrm{3}}+\mathrm{2}{x}\sqrt{\mathrm{3}}−\mathrm{3} \\ $$$$=\mathrm{4}{x}^{\mathrm{2}} −\mathrm{3} \\ $$
Answered by MJS_new last updated on 13/Oct/20
((√3)−1)((√3)+1)=(√3)×(√3)−(√3)+(√3)−1=3−1=2  (a−b)(a+b)=a^2 −b^2
$$\left(\sqrt{\mathrm{3}}−\mathrm{1}\right)\left(\sqrt{\mathrm{3}}+\mathrm{1}\right)=\sqrt{\mathrm{3}}×\sqrt{\mathrm{3}}−\sqrt{\mathrm{3}}+\sqrt{\mathrm{3}}−\mathrm{1}=\mathrm{3}−\mathrm{1}=\mathrm{2} \\ $$$$\left({a}−{b}\right)\left({a}+{b}\right)={a}^{\mathrm{2}} −{b}^{\mathrm{2}} \\ $$

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