1-3-4x-1-2x-2-x-2-dx-solve-

Question Number 22946 by ANTARES_VY last updated on 24/Oct/17

\underset{1}{\int^{3}} \frac{4 x + 1}{2 x^{2} + x - 2} dx ? solve

Answered by ajfour last updated on 24/Oct/17

= \ln 19

Answered by Joel577 last updated on 24/Oct/17

Let u = 2 x^{2} + x - 2 \to d u = 4 x + 1 d x

x = 1 \to u = 1

x = 3 \to u = 19

I = \underset{1}{\int^{19}} \frac{4 x + 1}{u} . \frac{d u}{4 x + 1}

= {[\ln u]}_{1}^{19} = \ln 19 - \ln 1 = \ln 19

Facebook Tweet Pin