Question Number 179140 by Shrinava last updated on 25/Oct/22

Answered by Frix last updated on 25/Oct/22

Commented by Frix last updated on 25/Oct/22

Answered by Rasheed.Sindhi last updated on 25/Oct/22
![3a=4b=6c ∧ a+b+c=27; a−c=? [ _( _( ) ) 3a=6c⇒a−2c=0⇒a−c=c_(Hence we need value of c) ] ▶Eleminating b from a+b+c=27 3a=4b=6c⇒ { ((b=(3/2)c)),((b=(3/4)a)) :} •a+b+c=27⇒a+(3/4)a+c=27 ⇒7a+4c=108....(i) •a+b+c=27⇒a+(3/2)c+c=27 ⇒2a+5c=54....(ii) ▶Eleminating a from (i) & (ii) { ((2×(i)⇒14a+8c=216)),((7×(ii)⇒14a+35c=378)) :}⇒27c=162 ⇒c=((162)/(27))=6 •3a=6c⇒a−2c=0⇒a−c=c=6](https://www.tinkutara.com/question/Q179142.png)
Answered by som(math1967) last updated on 25/Oct/22

Answered by Rasheed.Sindhi last updated on 25/Oct/22
