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1-3a-1-4b-1-6c-and-a-b-c-27-find-a-c-




Question Number 179140 by Shrinava last updated on 25/Oct/22
(1/(3a)) = (1/(4b)) = (1/(6c))   and   a+b+c=27  find   a−c=?
13a=14b=16canda+b+c=27findac=?
Answered by Frix last updated on 25/Oct/22
a=4t  b=3t  c=2t  a+b+c=27  9t=27  t=3  a=12  b=9  c=6  a−c=6
a=4tb=3tc=2ta+b+c=279t=27t=3a=12b=9c=6ac=6
Commented by Frix last updated on 25/Oct/22
yes thank you
yesthankyou
Answered by Rasheed.Sindhi last updated on 25/Oct/22
3a=4b=6c ∧ a+b+c=27; a−c=?  [ _(  _( ) ) 3a=6c⇒a−2c=0⇒a−c=c_(Hence   we need   value of  c)   ]  ▶Eleminating b from a+b+c=27  3a=4b=6c⇒ { ((b=(3/2)c)),((b=(3/4)a)) :}   •a+b+c=27⇒a+(3/4)a+c=27                              ⇒7a+4c=108....(i)  •a+b+c=27⇒a+(3/2)c+c=27                               ⇒2a+5c=54....(ii)  ▶Eleminating a from (i) & (ii)   { ((2×(i)⇒14a+8c=216)),((7×(ii)⇒14a+35c=378)) :}⇒27c=162                ⇒c=((162)/(27))=6  •3a=6c⇒a−2c=0⇒a−c=c=6
3a=4b=6ca+b+c=27;ac=?[3a=6ca2c=0ac=cHenceweneedvalueofc]Eleminatingbfroma+b+c=273a=4b=6c{b=32cb=34aa+b+c=27a+34a+c=277a+4c=108.(i)a+b+c=27a+32c+c=272a+5c=54.(ii)Eleminatingafrom(i)&(ii){2×(i)14a+8c=2167×(ii)14a+35c=37827c=162c=16227=63a=6ca2c=0ac=c=6
Answered by som(math1967) last updated on 25/Oct/22
(1/(3a))=(1/(4b))=(1/(6c))  3a=4b=6c  ((3a)/(12))=((4b)/(12))=((6c)/(12))  (a/4)=(b/3)=(c/2)=k (let)  ∴a=4k, b=3k,c=2k  a+b+c=27  ⇒4k+3k+2k=27  ⇒9k=27⇒k=3   a−c=4k−2k=2k=2×3=6
13a=14b=16c3a=4b=6c3a12=4b12=6c12a4=b3=c2=k(let)a=4k,b=3k,c=2ka+b+c=274k+3k+2k=279k=27k=3ac=4k2k=2k=2×3=6
Answered by Rasheed.Sindhi last updated on 25/Oct/22
(1/(3a)) = (1/(4b)) = (1/(6c))  ∧ a+b+c=27; a−c=?  (1/(3a)) = (1/(4b)) = (1/(6c))⇒((4×1)/(4(3a))) = ((3×1)/(3(4b))) = ((2×1)/(2(6c)))              =(9/(12(a+b+c)))=(3/(4×27))=(1/(36))        3a=36 ∧ 6c=36        3a=36 ∧ 3c=18        ⇒3a−3c=18        ⇒a−c=6
13a=14b=16ca+b+c=27;ac=?13a=14b=16c4×14(3a)=3×13(4b)=2×12(6c)=912(a+b+c)=34×27=1363a=366c=363a=363c=183a3c=18ac=6

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