Question Number 181872 by srikanth2684 last updated on 01/Dec/22
$$\underset{−\mathrm{1}} {\overset{\mathrm{4}} {\int}}\frac{\mathrm{1}}{\mid{x}\mid}\:{dx} \\ $$
Answered by Frix last updated on 01/Dec/22
$$\underset{−\mathrm{1}} {\overset{\mathrm{4}} {\int}}\frac{{dx}}{\mid{x}\mid}=\underset{\mathrm{0}} {\overset{\mathrm{1}} {\int}}\frac{{dx}}{{x}}+\underset{\mathrm{0}} {\overset{\mathrm{4}} {\int}}\frac{{dx}}{{x}}\:\mathrm{which}\:\mathrm{doesn}'\mathrm{t}\:\mathrm{converge} \\ $$