Question Number 151860 by maged last updated on 23/Aug/21

Commented by lyubita last updated on 23/Aug/21

Commented by lyubita last updated on 23/Aug/21

Commented by maged last updated on 23/Aug/21

Answered by puissant last updated on 23/Aug/21
![Q=∫_1 ^5 ∣2−∣3−x∣∣dx =∫_1 ^3 ∣2−3+x∣dx+∫_3 ^5 ∣2+3−x∣dx =∫_1 ^3 ∣x−1∣dx+∫_3 ^5 ∣5−x∣dx =[(x^2 /2)−x]_1 ^3 +[5x−(x^2 /2)]_3 ^5 =[((9/2)−3)−((1/2)−1)]+[(25−((25)/2))−(15−(9/2))] =2+2 =4 ∴∵ Q= ∫_1 ^5 ∣2−∣3−x∣∣dx = 4..](https://www.tinkutara.com/question/Q151868.png)
Commented by maged last updated on 23/Aug/21
