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1-5-x-f-x-dx-dx-24-1-3-2-f-x-dx-




Question Number 95624 by i jagooll last updated on 26/May/20
∫_1 ^5 x(∫f(x)dx) dx = 24  ∫_1 ^3 (2−f(x))dx ?
51x(f(x)dx)dx=2431(2f(x))dx?
Answered by Racoon last updated on 26/May/20
∫f(x)dx=2⇒∫_1 ^3 [2−f(x)]dx=2(3−1)−2=2
f(x)dx=213[2f(x)]dx=2(31)2=2
Commented by PRITHWISH SEN 2 last updated on 26/May/20
how ∫f(x)dx=2 ?
howf(x)dx=2?

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