1-8-10-6-tan-89-9999-pi-upto-9-decimal-places-can-i-have-some-explanations-how-it-is-worked-out-Thank-you-

Question Number 47239 by JDlix last updated on 06/Nov/18

\frac{1.8 \times 10^{6}}{t a n (89.9999 °)} \sim π (u p t o 9 d e c i m a l p l a c e s)

c a n i h a v e s o m e e x p l a n a t i o n s h o w i t i s w o r k e d o u t ?

T h a n k y o u!

Commented by MJS last updated on 07/Nov/18

I guess somebody just messed around a bit .

you can find many almost - identities

π \ln (π) = \frac{143851}{40000} (error \approx - 2.7 \times 10^{- 10})

π \ln (π \ln (π)) = \frac{100523}{25000} (error \approx - 2.6 \times 10^{- 10})

π = \frac{6955380174 - \sqrt{3}}{2213966271} (error \approx - 5 \times 10^{- 13})

Answered by MJS last updated on 07/Nov/18

\tan ((90 - \frac{1}{10^{d}}) °) = \frac{1}{\tan \frac{π}{180 \times 10^{d}}} \approx \frac{180 \times 10^{d}}{π} with d \in N

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