1-A-3152-A-1-2-Solve-the-equation-2×611-0-3-Calculate-the-determinant-132-21-13-42-

Question Number 124707 by Mammadli last updated on 05/Dec/20

1 . \boldsymbol A = (3152), \boldsymbol A^{- 1} = ?

2 . \boldsymbol S o l v e \boldsymbol t h e \boldsymbol e q u a t i o n :

∣ 2 \boldsymbol x 611 ∣= 0

3 . \boldsymbol C a l c u l a t e \boldsymbol t h e \boldsymbol d e t e r m i n a n t :

∣ 132 21 13 42 ∣

Commented by MJS_new last updated on 05/Dec/20

once you open a new question {there}^{'} s a menue

on top :

help ∣_{Color}^{Font &} ∣_{Drawing}^{Insert} ∣_{& Tables}^{Matrix} ∣ \dots

use this so we are able to understand what

you mean

Commented by Mammadli last updated on 05/Dec/20

Dear ser, was written as I wrote

Answered by liberty last updated on 05/Dec/20

d o y o u m e a n t A = (\begin{matrix} 3 1 \\ 5 2 \end{matrix}) ?

A^{- 1} = \frac{1}{6 - 5} (\begin{matrix} 2 - 1 \\ - 5 3 \end{matrix}) = (\begin{matrix} 2 - 1 \\ - 5 3 \end{matrix})

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