Menu Close

1-calculate-A-cos-pi-7-cos-2pi-7-cos-3pi-7-2-calculate-B-tan-pi-7-tan-2pi-7-tan-3pi-7-




Question Number 39028 by maxmathsup by imad last updated on 01/Jul/18
1) calculate  A=cos((π/7)).cos(((2π)/7)).cos(((3π)/7))  2) calculate B =tan((π/7)).tan(((2π)/7)).tan(((3π)/7)).
$$\left.\mathrm{1}\right)\:{calculate}\:\:{A}={cos}\left(\frac{\pi}{\mathrm{7}}\right).{cos}\left(\frac{\mathrm{2}\pi}{\mathrm{7}}\right).{cos}\left(\frac{\mathrm{3}\pi}{\mathrm{7}}\right) \\ $$$$\left.\mathrm{2}\right)\:{calculate}\:{B}\:={tan}\left(\frac{\pi}{\mathrm{7}}\right).{tan}\left(\frac{\mathrm{2}\pi}{\mathrm{7}}\right).{tan}\left(\frac{\mathrm{3}\pi}{\mathrm{7}}\right). \\ $$
Answered by tanmay.chaudhury50@gmail.com last updated on 02/Jul/18
A×2sin(Π/7)=2sin(Π/7)cos(Π/7)cos((2Π)/7)cos((3Π)/7)  A×2sin(Π/7)=sin((2Π)/7)cos((2Π)/7)cos((3Π)/7)  A×2^2 sin(Π/7)=sin((4Π)/7)cos((3Π)/7)  A×2^3 sin(Π/7)=2sin((4Π)/7)cos((3Π)/7)  A×2^3 sin(Π/7)=sinΠ+sin(Π/7)  A×2^3 sin(Π/7)=sin(Π/7)  A=(1/8)
$${A}×\mathrm{2}{sin}\frac{\Pi}{\mathrm{7}}=\mathrm{2}{sin}\frac{\Pi}{\mathrm{7}}{cos}\frac{\Pi}{\mathrm{7}}{cos}\frac{\mathrm{2}\Pi}{\mathrm{7}}{cos}\frac{\mathrm{3}\Pi}{\mathrm{7}} \\ $$$${A}×\mathrm{2}{sin}\frac{\Pi}{\mathrm{7}}={sin}\frac{\mathrm{2}\Pi}{\mathrm{7}}{cos}\frac{\mathrm{2}\Pi}{\mathrm{7}}{cos}\frac{\mathrm{3}\Pi}{\mathrm{7}} \\ $$$${A}×\mathrm{2}^{\mathrm{2}} {sin}\frac{\Pi}{\mathrm{7}}={sin}\frac{\mathrm{4}\Pi}{\mathrm{7}}{cos}\frac{\mathrm{3}\Pi}{\mathrm{7}} \\ $$$${A}×\mathrm{2}^{\mathrm{3}} {sin}\frac{\Pi}{\mathrm{7}}=\mathrm{2}{sin}\frac{\mathrm{4}\Pi}{\mathrm{7}}{cos}\frac{\mathrm{3}\Pi}{\mathrm{7}} \\ $$$${A}×\mathrm{2}^{\mathrm{3}} {sin}\frac{\Pi}{\mathrm{7}}={sin}\Pi+{sin}\frac{\Pi}{\mathrm{7}} \\ $$$${A}×\mathrm{2}^{\mathrm{3}} {sin}\frac{\Pi}{\mathrm{7}}={sin}\frac{\Pi}{\mathrm{7}} \\ $$$${A}=\frac{\mathrm{1}}{\mathrm{8}} \\ $$

Leave a Reply

Your email address will not be published. Required fields are marked *