1-cos-x-3-sin-x-4- Tinku Tara June 4, 2023 Trigonometry 0 Comments FacebookTweetPin Question Number 106295 by bobhans last updated on 04/Aug/20 1cosx+3sinx=4 Answered by bemath last updated on 04/Aug/20 sinx+3cosx=4sinxcosx12sinx+32cosx=sin2xsin30°sinx+cos30°cosx=sin2xcos(30°−x)=sin2x=cos(90°−2x){30°−x=90°−2x+k.360°30°−x=−90°+2x+k.360°{x=60°+k.360°x=40°+k.120° Answered by Dwaipayan Shikari last updated on 04/Aug/20 sinx+3cosx=4sinxcosx12sinx+32cosx=sin2xsin(x+π3)=sin2x2x=2πk±(x+π3)x=2πk+π3=(6k+1)π3(k∈Z)3x=2πk−π3x=(6k−1)π9 Terms of Service Privacy Policy Contact: info@tinkutara.com FacebookTweetPin Post navigation Previous Previous post: solve-for-x-y-z-xy-3x-2y-6-yz-y-3z-3-zx-2z-x-2-Next Next post: solve-for-x-2log-x-4-log-2-x- Leave a Reply Cancel replyYour email address will not be published. Required fields are marked *Comment * Name * Save my name, email, and website in this browser for the next time I comment.