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1-cosx-99cosx-70sinx-210-cosx-66sinx-110-dx-




Question Number 106075 by Her_Majesty last updated on 02/Aug/20
∫((1+cosx)/((99cosx−70sinx+210)cosx−66sinx+110))dx=?
$$\int\frac{\mathrm{1}+{cosx}}{\left(\mathrm{99}{cosx}−\mathrm{70}{sinx}+\mathrm{210}\right){cosx}−\mathrm{66}{sinx}+\mathrm{110}}{dx}=? \\ $$
Answered by Dwaipayan Shikari last updated on 02/Aug/20
From wolfram Alpha
$${From}\:{wolfram}\:{Alpha} \\ $$
Commented by Dwaipayan Shikari last updated on 02/Aug/20
Commented by Her_Majesty last updated on 02/Aug/20
it should be possible using elementary calculus
$${it}\:{should}\:{be}\:{possible}\:{using}\:{elementary}\:{calculus} \\ $$

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