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1-d-sin-2-tan-3-2-d-cos-2-cos-3-3-d-sinh-2-tanh-3-4-d-cosh-2-cosh-3-

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Question Number 40251 by MJS last updated on 17/Jul/18
1. ∫(dα/(sin 2α +tan 3α))=? 2. ∫(dβ/(cos 2β +cos 3β))=? 3. ∫(dγ/(sinh 2γ +tanh 3γ))=? 4. ∫(dδ/(cosh 2δ +cosh 3δ))=?
$$\mathrm{1}.\:\:\:\:\:\int\frac{{d}\alpha}{\mathrm{sin}\:\mathrm{2}\alpha\:+\mathrm{tan}\:\mathrm{3}\alpha}=? \\ $$$$\mathrm{2}.\:\:\:\:\:\int\frac{{d}\beta}{\mathrm{cos}\:\mathrm{2}\beta\:+\mathrm{cos}\:\mathrm{3}\beta}=? \\ $$$$\mathrm{3}.\:\:\:\:\:\int\frac{{d}\gamma}{\mathrm{sinh}\:\mathrm{2}\gamma\:+\mathrm{tanh}\:\mathrm{3}\gamma}=? \\ $$$$\mathrm{4}.\:\:\:\:\:\int\frac{{d}\delta}{\mathrm{cosh}\:\mathrm{2}\delta\:+\mathrm{cosh}\:\mathrm{3}\delta}=? \\ $$
Answered by maxmathsup by imad last updated on 26/Jul/18
4) let I = ∫ (dx/(ch(2x)+ch(3x))) I = ∫ (dx/(((e^(2x) +e^(−2x) )/2)+((e^(3x) +e^(−3x) )/2))) =∫ ((2dx)/(e^(2x) +e^(−2x) +e^(3x) +e^(−3x) )) =_(e^x =t) ∫ (2/(t^2 +t^(−2) +t^3 +t^(−3) )) (dt/t) = ∫ ((2dt)/(t^3 +t^(−1) +t^4 +t^(−2) )) = ∫ ((t^2 dt)/(t^2 (t^3 +t^(−1) +t^4 +t^(−2) ))) = ∫ ((t^2 dt)/(t^5 +t +t^6 +1)) =∫ ((t^2 dt)/(t^6 +t^5 +t+1)) roots of p(t)=t^6 +t^5 +t+1 t_1 =−1 (double) t_2 ∼0,809 +0,587i (complex) t_3 =0,809−0,587i (complex) t_4 ∼−0,309 +0,9511i(complex) t_5 ∼ −0,309 −0,9511i(complex) p(t) =(t+1)^2 ( t−t_2 )(t−t_2 ^− )(t−t_4 )(t−t_4 ^− ) ⇒ F(t)= (t^2 /((t+1)^2 (t^2 −2Re(t_2 )t +∣t_2 ∣^2 )(t^2 −2Re(t_4 )t +∣t_4 ∣^2 ))) = (a/(t+1)) +(b/((t+1)^2 )) +((ct +d)/(t^2 −2Re(t_2 )t +∣t∣^2 )) + ((et +f)/(t^2 −2Re(t_4 )t +∣t_4 ∣^2 )) ...be continued...
$$\left.\mathrm{4}\right)\:{let}\:{I}\:=\:\int\:\:\:\frac{{dx}}{{ch}\left(\mathrm{2}{x}\right)+{ch}\left(\mathrm{3}{x}\right)} \\ $$$${I}\:=\:\int\:\:\:\:\frac{{dx}}{\frac{{e}^{\mathrm{2}{x}} \:+{e}^{−\mathrm{2}{x}} }{\mathrm{2}}+\frac{{e}^{\mathrm{3}{x}} \:+{e}^{−\mathrm{3}{x}} }{\mathrm{2}}}\:=\int\:\:\:\:\:\frac{\mathrm{2}{dx}}{{e}^{\mathrm{2}{x}} \:+{e}^{−\mathrm{2}{x}} \:+{e}^{\mathrm{3}{x}} \:+{e}^{−\mathrm{3}{x}} } \\ $$$$=_{{e}^{{x}} ={t}} \:\:\:\:\int\:\:\:\frac{\mathrm{2}}{{t}^{\mathrm{2}} \:+{t}^{−\mathrm{2}} \:+{t}^{\mathrm{3}} \:+{t}^{−\mathrm{3}} }\:\frac{{dt}}{{t}}\:=\:\int\:\:\:\:\frac{\mathrm{2}{dt}}{{t}^{\mathrm{3}} \:+{t}^{−\mathrm{1}} \:+{t}^{\mathrm{4}} \:+{t}^{−\mathrm{2}} } \\ $$$$=\:\int\:\:\:\:\frac{{t}^{\mathrm{2}} {dt}}{{t}^{\mathrm{2}} \left({t}^{\mathrm{3}} \:+{t}^{−\mathrm{1}} \:+{t}^{\mathrm{4}} \:+{t}^{−\mathrm{2}} \right)}\:=\:\int\:\:\:\frac{{t}^{\mathrm{2}} {dt}}{{t}^{\mathrm{5}} \:+{t}\:+{t}^{\mathrm{6}} \:+\mathrm{1}}\:=\int\:\:\frac{{t}^{\mathrm{2}} {dt}}{{t}^{\mathrm{6}} \:+{t}^{\mathrm{5}} \:+{t}+\mathrm{1}} \\ $$$${roots}\:{of}\:\:{p}\left({t}\right)={t}^{\mathrm{6}} \:+{t}^{\mathrm{5}} \:+{t}+\mathrm{1} \\ $$$${t}_{\mathrm{1}} =−\mathrm{1}\:\left({double}\right) \\ $$$${t}_{\mathrm{2}} \sim\mathrm{0},\mathrm{809}\:+\mathrm{0},\mathrm{587}{i}\:\left({complex}\right) \\ $$$${t}_{\mathrm{3}} =\mathrm{0},\mathrm{809}−\mathrm{0},\mathrm{587}{i}\:\left({complex}\right) \\ $$$${t}_{\mathrm{4}} \sim−\mathrm{0},\mathrm{309}\:+\mathrm{0},\mathrm{9511}{i}\left({complex}\right) \\ $$$${t}_{\mathrm{5}} \:\sim\:−\mathrm{0},\mathrm{309}\:−\mathrm{0},\mathrm{9511}{i}\left({complex}\right) \\ $$$${p}\left({t}\right)\:=\left({t}+\mathrm{1}\right)^{\mathrm{2}} \left(\:{t}−{t}_{\mathrm{2}} \right)\left({t}−\overset{−} {{t}}_{\mathrm{2}} \right)\left({t}−{t}_{\mathrm{4}} \right)\left({t}−\overset{−} {{t}}_{\mathrm{4}} \right)\:\Rightarrow \\ $$$${F}\left({t}\right)=\:\frac{{t}^{\mathrm{2}} }{\left({t}+\mathrm{1}\right)^{\mathrm{2}} \left({t}^{\mathrm{2}} −\mathrm{2}{Re}\left({t}_{\mathrm{2}} \right){t}\:\:+\mid{t}_{\mathrm{2}} \mid^{\mathrm{2}} \right)\left({t}^{\mathrm{2}} \:−\mathrm{2}{Re}\left({t}_{\mathrm{4}} \right){t}\:+\mid{t}_{\mathrm{4}} \mid^{\mathrm{2}} \right)} \\ $$$$=\:\frac{{a}}{{t}+\mathrm{1}}\:+\frac{{b}}{\left({t}+\mathrm{1}\right)^{\mathrm{2}} }\:+\frac{{ct}\:+{d}}{{t}^{\mathrm{2}} \:−\mathrm{2}{Re}\left({t}_{\mathrm{2}} \right){t}\:+\mid{t}\mid^{\mathrm{2}} }\:+\:\frac{{et}\:+{f}}{{t}^{\mathrm{2}} −\mathrm{2}{Re}\left({t}_{\mathrm{4}} \right){t}\:+\mid{t}_{\mathrm{4}} \mid^{\mathrm{2}} }\:\:…{be}\:{continued}… \\ $$

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