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1-e-pi-cos-lnx-x-dx-




Question Number 91904 by Ar Brandon last updated on 03/May/20
∫_1 ^e^π  ((cos(lnx))/x)dx
1eπcos(lnx)xdx
Commented by Prithwish Sen 1 last updated on 03/May/20
put ln(x)=t
putln(x)=t
Commented by Ar Brandon last updated on 03/May/20
Okay, let me try. Thanks
Okay,letmetry.Thanks
Commented by mathmax by abdo last updated on 03/May/20
I =∫_1 ^e^π   ((cos(lnx))/x)dx vhangement lnx =t give   I =∫_0 ^π  ((cos(t))/e^t ) e^t  dt =∫_0 ^π  cost dt =[sint]_0 ^π  =0
I=1eπcos(lnx)xdxvhangementlnx=tgiveI=0πcos(t)etetdt=0πcostdt=[sint]0π=0
Answered by Ar Brandon last updated on 03/May/20

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