1-find-f-a-e-ax-2-cos-3-x-2-dx-with-a-gt-0-2-find-the-value-of-0-e-3x-2-cos-3-x-2-dx- Tinku Tara June 4, 2023 Integration 0 Comments FacebookTweetPin Question Number 65286 by mathmax by abdo last updated on 27/Jul/19 1)findf(a)=∫−∞+∞e−ax2cos(3−x2)dxwitha>02)findthevalueof∫0∞e−3x2cos(3−x2)dx Commented by mathmax by abdo last updated on 29/Jul/19 1)wehavef(a)=∫−∞+∞e−ax2cos(3−x2)dx⇒f(a)=Re(∫−∞+∞e−ax2+i(3−x2)dx)I=∫−∞+∞e−ax2+i(3−x2)dx=e3i∫−∞+∞e−(a+i)x2dxchangementa+ix=tgiveI=e3i∫−∞+∞e−t2dta+i=e3ia+iπa+i=1+a2{a1+a2+i1+a2}=reiθ⇒r=1+a2andθ=arctan(1a)a+i=rei2θ=(1+a2)14ei2arctan(1a)=41+a2ei2(π2−arctana)=41+a2eiπ4−i2arctana⇒I=πe3i(41+a2)eiπ4−i2arctan(a)=π(41+a2)e3i−iπ4+i2arctan(a)=π(41+a2)ei(3−π4+12arctan(a))⇒f(a)=π(41+a2)cos(3−π4+arctana2).2)∫0∞e−3x2cos(3−x2)dx=12∫−∞+∞e−3x2cos(3−x2)dx=12f(3)=π(410)cos(3−π4+arctan(3)2) Commented by mathmax by abdo last updated on 29/Jul/19 ∫0∞e−3x2cos(3−x2)dx=π2(410)cos(3−π4+arctan(3)2) Terms of Service Privacy Policy Contact: info@tinkutara.com FacebookTweetPin Post navigation Previous Previous post: if-z-1-z-2-z-3-1-and-1-z-1-1-z-2-1-z-3-1-find-z-1-z-2-z-3-z-1-z-2-z-3-complex-number-Next Next post: let-f-x-x-x-2pi-periodic-odd-developp-f-at-fourier-series- Leave a Reply Cancel replyYour email address will not be published. Required fields are marked *Comment * Name * Save my name, email, and website in this browser for the next time I comment.