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1-find-u-the-value-of-u-if-n-1-4-2u-2-n-1-64-2-find-k-if-n-1-k-1-3-n-1-2-3-




Question Number 32707 by Rio Mike last updated on 31/Mar/18
1)find u the value of u if  Σ_(n=1) ^4 2u.2^(n−1) =64  2) find k if    Σ_(n=1) ^∞ k.((1/3))^(n−1) =(2/3)
1)finduthevalueofuifn=142u.2n1=642)findkifn=1k.(13)n1=23
Answered by MJS last updated on 31/Mar/18
Σ_(n=1) ^4 2u×2^(n−1) =2uΣ_(n=1) ^4 2^(n−1) =  =2u(1+2+4+8)=30u  u=((64)/(30))=((32)/(15))    Σ_(n=1) ^∞ k×((1/3))^(n−1) =kΣ_(n=0) ^∞ (1/3^n )=k×(3/2)  ((3k)/2)=(2/3)  k=(4/9)
4n=12u×2n1=2u4n=12n1==2u(1+2+4+8)=30uu=6430=3215n=1k×(13)n1=kn=013n=k×323k2=23k=49
Commented by NECx last updated on 02/Apr/18
how did Σ_(n=0) ^∝ k×(1/3)^(n−1 ) become 3k/2  ???
howdidn=0k×(1/3)n1become3k/2???

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