1-i-2-i-2-i-1-i-3-500x-500yi-find-x-y- Tinku Tara June 4, 2023 Others 0 Comments FacebookTweetPin Question Number 80890 by M±th+et£s last updated on 07/Feb/20 (1+i2−i+2+i1−i)3=500x+500yifindx,y Answered by behi83417@gmail.com last updated on 07/Feb/20 (1+i)(2+i)2+1=2+i+2i+13=3+3i3=1+i2+i1−i=(2+i)(1+i)1+1=2+2i+i+12=3+3i2LHS=[1+i+32(1+i)]3=[52(1+i)]3==1258(1+3i+3i2+i3)=1258(1+3i−3−i)==1258(2i−2)=1254(i−1)=500x+500yi⇒i−1=16x+16yi⇒{x=−116y=116. Commented by M±th+et£s last updated on 07/Feb/20 thankyousir Terms of Service Privacy Policy Contact: info@tinkutara.com FacebookTweetPin Post navigation Previous Previous post: find-Z-if-arg-z-3-pi-and-arg-z-i-pi-4-Next Next post: If-a-b-c-are-mutually-perpendicular-vectors-of-equal-magnitudes-show-that-the-vector-a-b-c-is-equally-inclined-to-a-b-and-c- Leave a Reply Cancel replyYour email address will not be published. Required fields are marked *Comment * Name * Save my name, email, and website in this browser for the next time I comment.
![(((1+i)(2+i))/(2+1))=((2+i+2i+1)/3)=((3+3i)/3)=1+i ((2+i)/(1−i))=(((2+i)(1+i))/(1+1))=((2+2i+i+1)/2)=((3+3i)/2) LHS=[1+i+(3/2)(1+i)]^3 =[(5/2)(1+i)]^3 = =((125)/8)(1+3i+3i^2 +i^3 )=((125)/8)(1+3i−3−i)= =((125)/8)(2i−2)=((125)/4)(i−1)=500x+500yi ⇒i−1=16x+16yi⇒ { ((x=((−1)/(16)))),((y=(1/(16)))) :} .](https://www.tinkutara.com/question/Q80898.png)
