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1-If-p-and-q-are-the-roots-quadratic-equation-x-2-x-4050-0-find-the-value-of-p-2-q-2-if-f-x-7x-q-2-and-g-x-7x-8-fog-4-24-find-the-value-of-q-




Question Number 103458 by bobhans last updated on 15/Jul/20
(1)If p and q are the roots quadratic  equation x^2 −x−4050 = 0 , find the value  of p^2 +q ?   (2) if f(x)=((7x+q)/2) and g(x)=7x+8 ;  (fog)(4) = 24 . find the value of q
(1)Ifpandqaretherootsquadraticequationx2x4050=0,findthevalueofp2+q?(2)iff(x)=7x+q2andg(x)=7x+8;(fog)(4)=24.findthevalueofq
Answered by bemath last updated on 15/Jul/20
(1) x^2 −x−4050=0→ { (p),(q) :}  ⇔p^2  = p+4050  then p^2 +q = p+4050+q  = p+q +4050  = 1+4050 = 4051 ;(by Vieta′s  rule )★
(1)x2x4050=0{pqp2=p+4050thenp2+q=p+4050+q=p+q+4050=1+4050=4051;(byVietasrule)
Answered by bemath last updated on 15/Jul/20
(2)(fog)(4)= f(g(4))  ⇒g(4)= 7.4 + 8 = 36   ⇒f(36) = 24 →((7.36+q)/2) = 24  q = 48−252 = −204 ★
(2)(fog)(4)=f(g(4))g(4)=7.4+8=36f(36)=247.36+q2=24q=48252=204

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