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1-If-x-2-2-y-2-x-2-2-y-2-6-show-that-when-the-equation-is-simplified-it-can-be-express-as-x-2-9-y-2-5-1-2-find-the-value-of-n-such-that-the-linear-factors-of-the-form-x




Question Number 53500 by Otchere Abdullai last updated on 22/Jan/19
1. If  (√((x+2)^(2 ) +y^2 ))+(√((x−2)^2 +y^2 ))=6  show that when the equation is   simplified, it can be express as  (x^2 /9)+(y^2 /5)=1  2. find the value of n such that the  linear factors of the form x+ay+b   and x+cy+d with integer coefficients  have the product x^2 +5xy+x+ny−n  sir please help
1.If(x+2)2+y2+(x2)2+y2=6showthatwhentheequationissimplified,itcanbeexpressasx29+y25=12.findthevalueofnsuchthatthelinearfactorsoftheformx+ay+bandx+cy+dwithintegercoefficientshavetheproductx2+5xy+x+nynsirpleasehelp
Answered by tanmay.chaudhury50@gmail.com last updated on 22/Jan/19
(√((x+2)^2 +y^2 )) =6−(√((x−2)^2 +y^2 ))   x^2 +4x+4+y^2 =36−12(√((x−2)^2 +y^2 )) +x^2 −4x+4+y^2   cancelling x^2 ,y^2 ,4 from both side  4x=36−12(√(x^2 −4x+4+y^2 )) −4x  8x−36=−12(√(x^2 −4x+4+y^2 ))   2x−9=−3(√(x^2 −4x+4+y^2 ))   4x^2 −36x+81=9x^2 −36x+36+9y^2   5x^2 +9y^2 =45  (x^2 /9)+(y^2 /5)=1
(x+2)2+y2=6(x2)2+y2x2+4x+4+y2=3612(x2)2+y2+x24x+4+y2cancellingx2,y2,4frombothside4x=3612x24x+4+y24x8x36=12x24x+4+y22x9=3x24x+4+y24x236x+81=9x236x+36+9y25x2+9y2=45x29+y25=1
Commented by Otchere Abdullai last updated on 22/Jan/19
wow! thank you sir God bless you
wow!thankyousirGodblessyou
Answered by tanmay.chaudhury50@gmail.com last updated on 22/Jan/19
2)(x+ay+b)(x+cy+d)=x^2 +5xy+x+ny−n  x^2 +cxy+xd+axy+acy^2 +ayd+bx+bcy+bd=x^2 +5xy+x+ny−n  x^2 +xy(a+c)+x(b+d)+y(ad+bc)+acy^2 +bd=x^2 +5xy+x+ny−n  so  a+c=5  b+d=1  ad+bc=n  ac=0  bd=−n  ac=0  a(5−a)=0   either a=0 or a=5  when  a=0  c=5  and when a=5  c=0  now let a=0  c.=5  ad+bc=n  0×d+b×5=n   [b=(n/5)]  a=0  b=(n/5)  c=5  d=1−b=1−(n/5)  bd=−n  ((n/5))×(1−(n/5))=−n  (1/5)×(((5−n)/5))=−1  5−n=−25  −n=−30 ...n=30
2)(x+ay+b)(x+cy+d)=x2+5xy+x+nynx2+cxy+xd+axy+acy2+ayd+bx+bcy+bd=x2+5xy+x+nynx2+xy(a+c)+x(b+d)+y(ad+bc)+acy2+bd=x2+5xy+x+nynsoa+c=5b+d=1ad+bc=nac=0bd=nac=0a(5a)=0eithera=0ora=5whena=0c=5andwhena=5c=0nowleta=0c.=5ad+bc=n0×d+b×5=n[b=n5]a=0b=n5c=5d=1b=1n5bd=n(n5)×(1n5)=n15×(5n5)=15n=25n=30n=30
Commented by Otchere Abdullai last updated on 22/Jan/19
powerful  Mathematician! We thank  God for having you in the group  God bless you sir!
powerfulMathematician!WethankGodforhavingyouinthegroupGodblessyousir!
Commented by tanmay.chaudhury50@gmail.com last updated on 22/Jan/19
mathematics...activates ones mind to think...
mathematicsactivatesonesmindtothink

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