1-In-a-single-throw-of-three-dice-find-the-probability-of-getting-a-total-of-i-4-ii-at-most-4-iii-atleast-4-

Question Number 25559 by das47955@mail.com last updated on 11/Dec/17

(1) In a single throw of three

dice, find the probability of getting

a total of

(i) 4

(ii) at most 4

(iii) atleast 4

Commented by prakash jain last updated on 11/Dec/17

total number of outcomes = 6 \times 6 \times 6 = 216

4 : total number of favorable outcomes

1 + 2 + 1

1 + 1 + 2

2 + 1 + 1

3

probability of getting a 4 = \frac{3}{216}

(ii) at most 4 (3 and 4)

1 + 1 + 1 = 3

probability of getting at most 4 = \frac{4}{216}

(iii) at least 4 .

there is only 1 unfavorable outcome

1 + 1 + 1 = 3

probability = 1 - \frac{1}{216} = \frac{215}{216}

Commented by Rasheed.Sindhi last updated on 11/Dec/17

Salute to my math - guru!