1-log-x-1-log-x-2-dx-

Question Number 152160 by peter frank last updated on 26/Aug/21

\int [\frac{1}{\log x} - \frac{1}{{(\log x)}^{2}}] dx

Answered by Olaf_Thorendsen last updated on 26/Aug/21

F (x) = \int (\frac{1}{\log x} - \frac{1}{\log^{2} x}) d x

F (x) = \int \frac{\log x - 1}{\log^{2} x} d x

F (x) = \int \frac{d}{d x} (\frac{x}{\log x}) d x

F (x) = \frac{x}{\log x} + C

Commented by puissant last updated on 26/Aug/21

j o l i e!

Commented by peter frank last updated on 26/Aug/21

thank you