Question Number 154860 by Jamshidbek last updated on 22/Sep/21
$$\frac{\mathrm{1}}{\mathrm{n}+\mathrm{1}}+\frac{\mathrm{1}}{\mathrm{n}+\mathrm{2}}+\frac{\mathrm{1}}{\mathrm{n}+\mathrm{3}}+…+\frac{\mathrm{1}}{\mathrm{2n}}<\frac{\mathrm{3}}{\mathrm{4}}\:\mathrm{n}>\mathrm{1} \\ $$$$\mathrm{Prove}\:\mathrm{that} \\ $$