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1-Prove-by-recurrence-that-for-n-28-n-11-n-2-On-subtract-the-limit-of-the-suite-n-10-n-when-n-tended-at-




Question Number 159078 by LEKOUMA last updated on 12/Nov/21
1) Prove by recurrence that   for n≥28,   n!≥11^n    2) On subtract the limit of the   suite (((n!)/(10^n ))) when n tended at +∞
1)Provebyrecurrencethatforn28,n!11n2)Onsubtractthelimitofthesuite(n!10n)whenntendedat+

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