1-sec-x-lt-2tan-x-on-0-2pi-2-find-the-cirtical-points-and-the-range-of-f-x-x-3-2x-1-

Question Number 84627 by M±th+et£s last updated on 14/Mar/20

1) ∣ s e c (x) ∣< 2 t a n (x) o n [0, 2 π]

2) f i n d t h e c i r t i c a l p o i n t s a n d t h e r a n g e o f

f (x) =∣ x - 3 ∣ + ∣ 2 x + 1 ∣

Commented by TANMAY PANACEA last updated on 14/Mar/20

w h a t i s w u e s t i o n n o 1

Commented by M±th+et£s last updated on 14/Mar/20

s o l v e t h e i n e q u a l i t y

Answered by TANMAY PANACEA last updated on 14/Mar/20

2) f (x) =∣ x - 3 ∣ + ∣ 2 x + 1 ∣

c r i t i c a l v a l u e o f x a r e 3, - 0.5

f (x) = x - 3 + 2 x + 1

= 3 x - 2 w h e n x > 3

= 7 w h e n x = 3

= - (x - 3) - (2 x + 1) x < - 0.5

= - 3 x + 2

= 3.5 w h e n x = - 0.5

= - (x - 3) + 2 x + 1 w h e n 3 > x > - 0.5

= x + 4

s o f (x) \in [3.5, \infty)

Commented by jagoll last updated on 14/Mar/20

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