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1-show-that-lim-n-2-2022-n-2-3-n-0-




Question Number 173401 by DAVONG last updated on 11/Jul/22
1.show that lim_(n→+∝) ((2^(2022) n^2 )/3^n )=0 ?
1.showthatlimn+22022n23n=0?
Commented by alephzero last updated on 11/Jul/22
lim_(n→∞) ((2^(2022) n^2 )/3^n ) = 2^(2022)  lim_(n→∞) (n^2 /3^n ) = 2^(2022) ×0  = 0  ★lim_(n→∞) (n^a /α^n ) = 0 ∀a ∀α
limn22022n23n=22022limnn23n=22022×0=0limnnaαn=0aα

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