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Question Number 109754 by joki last updated on 25/Aug/20
1.specify value absolute x if ?    b.∣2x+3∣+x−3=0
1.specifyvalueabsolutexif?b.2x+3+x3=0
Answered by Her_Majesty last updated on 25/Aug/20
∣((3x+1)/(x−2))∣=1  (1) x<−1/3  ((3x+1)/(x−2))=1 ⇔ x=−3/2  (2) −1/3≤x<2  −((3x+1)/(x−2))=1 ⇔ x=1/4  (3) 2<x  no solution  ⇒ x=−3/2∨x=1/4    ∣2x+3∣+x−3=0  (1) x<−3/2  −(2x+3)+x−3=0 ⇔ x=−6  (2) x≥−3/2  2x+3+x−3=0 ⇔ x=0  ⇒ x=−6∨x=0
3x+1x2∣=1(1)x<1/33x+1x2=1x=3/2(2)1/3x<23x+1x2=1x=1/4(3)2<xnosolutionx=3/2x=1/42x+3+x3=0(1)x<3/2(2x+3)+x3=0x=6(2)x3/22x+3+x3=0x=0x=6x=0

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