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1-x-2-y-8xy-12y-0-

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Question Number 118156 by bemath last updated on 15/Oct/20
(1−x^2 )y′′−8xy′−12y=0
$$\left(\mathrm{1}−{x}^{\mathrm{2}} \right){y}''−\mathrm{8}{xy}'−\mathrm{12}{y}=\mathrm{0} \\ $$
Commented by TANMAY PANACEA last updated on 15/Oct/20
still searching the way to reach goal
$${still}\:{searching}\:{the}\:{way}\:{to}\:{reach}\:{goal} \\ $$
Commented by SANOGO last updated on 30/Aug/21

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