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1-z-1-z-Where-z-is-the-complex-number-




Question Number 185371 by Mastermind last updated on 20/Jan/23
(1−z)(1−z^− ) = ?  Where z is the complex number    .
(1z)(1z)=?Wherezisthecomplexnumber.
Answered by Frix last updated on 20/Jan/23
z=a+bi∧z^� =a−bi  ⇒  (1−z)(1−z^� )=a^2 −2a+b^2 +1=(a−1)^2 +b^2 =  =(real (z) −1)^2 +(imag (z))^2
z=a+biz¯=abi(1z)(1z¯)=a22a+b2+1=(a1)2+b2==(real(z)1)2+(imag(z))2

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