Question Number 48830 by ggny last updated on 29/Nov/18
$$\mathrm{10}\frac{\mathrm{47}}{\mathrm{60}}−\left(\mathrm{8}\frac{\mathrm{1}}{\mathrm{5}}−\mathrm{5}\frac{\mathrm{2}}{\mathrm{3}}\right)×\frac{\mathrm{5}}{\mathrm{8}}\:\:\:\:{sir}\:{could}\:{you}\:{help}\:{me} \\ $$$$ \\ $$
Answered by tanmay.chaudhury50@gmail.com last updated on 29/Nov/18
$$\left(\mathrm{10}+\frac{\mathrm{47}}{\mathrm{60}}\right)−\left\{\left(\mathrm{8}+\frac{\mathrm{1}}{\mathrm{5}}\right)−\left(\mathrm{5}+\frac{\mathrm{2}}{\mathrm{3}}\right)\right\}×\frac{\mathrm{5}}{\mathrm{8}} \\ $$$$\left(\mathrm{10}+\frac{\mathrm{47}}{\mathrm{60}}\right)−\left\{\mathrm{8}−\mathrm{5}+\frac{\mathrm{1}}{\mathrm{5}}−\frac{\mathrm{2}}{\mathrm{3}}\right\}×\frac{\mathrm{5}}{\mathrm{8}} \\ $$$$\left(\mathrm{10}+\frac{\mathrm{47}}{\mathrm{60}}\right)−\left\{\mathrm{3}+\frac{\mathrm{3}−\mathrm{10}}{\mathrm{15}}\right\}×\frac{\mathrm{5}}{\mathrm{8}} \\ $$$$\left(\mathrm{10}+\frac{\mathrm{47}}{\mathrm{60}}\right)−\left(\frac{\mathrm{45}−\mathrm{7}}{\mathrm{15}}\right)×\frac{\mathrm{5}}{\mathrm{8}} \\ $$$$\left(\mathrm{10}+\frac{\mathrm{47}}{\mathrm{60}}\right)−\left(\frac{\mathrm{38}}{\mathrm{5}}×\frac{\mathrm{5}}{\mathrm{8}}\right) \\ $$$$\left(\mathrm{10}+\frac{\mathrm{47}}{\mathrm{60}}\right)−\left(\frac{\mathrm{19}}{\mathrm{4}}\right) \\ $$$$=\left(\mathrm{10}+\frac{\mathrm{47}}{\mathrm{60}}\right)−\left(\mathrm{4}+\frac{\mathrm{3}}{\mathrm{4}}\right) \\ $$$$=\mathrm{10}−\mathrm{4}+\frac{\mathrm{47}}{\mathrm{60}}−\frac{\mathrm{3}}{\mathrm{4}} \\ $$$$=\mathrm{6}+\frac{\mathrm{47}−\mathrm{45}}{\mathrm{60}} \\ $$$$=\mathrm{6}+\frac{\mathrm{2}}{\mathrm{60}} \\ $$$$=\mathrm{6}+\frac{\mathrm{1}}{\mathrm{30}} \\ $$$$=\mathrm{6}\frac{\mathrm{1}}{\mathrm{30}} \\ $$