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100-100-100-100-w-100-w-2-100-w-100-w-2-100-w-100-w-200-w-100-w-200-1-w-100-1-w-100-1-w-1-w-2




Question Number 191614 by vishal1234 last updated on 27/Apr/23
((α^(100) +β^(100) )/(α^(100) −β^(100) )) =   (((−w)^(100) +(−w^2 )^(100) )/((−w)^(100) −(−w^2 )^(100) ))  = ((w^(100) +w^(200) )/(w^(100) −w^(200) ))  = ((1+w^(100) )/(1−w^(100 ) ))  = ((1+w)/(1−w)) = (2/(2w)) = (1/w) =
$$\frac{\alpha^{\mathrm{100}} +\beta^{\mathrm{100}} }{\alpha^{\mathrm{100}} −\beta^{\mathrm{100}} }\:=\: \\ $$$$\frac{\left(−{w}\right)^{\mathrm{100}} +\left(−{w}^{\mathrm{2}} \right)^{\mathrm{100}} }{\left(−{w}\right)^{\mathrm{100}} −\left(−{w}^{\mathrm{2}} \right)^{\mathrm{100}} } \\ $$$$=\:\frac{{w}^{\mathrm{100}} +{w}^{\mathrm{200}} }{{w}^{\mathrm{100}} −{w}^{\mathrm{200}} } \\ $$$$=\:\frac{\mathrm{1}+{w}^{\mathrm{100}} }{\mathrm{1}−{w}^{\mathrm{100}\:} } \\ $$$$=\:\frac{\mathrm{1}+{w}}{\mathrm{1}−{w}}\:=\:\frac{\mathrm{2}}{\mathrm{2}{w}}\:=\:\frac{\mathrm{1}}{{w}}\:=\: \\ $$
Commented by Tinku Tara last updated on 27/Apr/23
Q191611
$${Q}\mathrm{191611} \\ $$

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