Question Number 148994 by gsk2684 last updated on 02/Aug/21
$$\left(\mathrm{102}\right)^{\mathrm{4}} \\ $$$${easy}\:{way}\:{to}\:{caculate} \\ $$
Answered by iloveisrael last updated on 02/Aug/21
$$\left(\mathrm{100}+\mathrm{2}\right)^{\mathrm{4}} =\underset{\mathrm{n}=\mathrm{0}} {\overset{\mathrm{4}} {\sum}}\mathrm{C}_{\mathrm{k}} ^{\mathrm{4}} \left(\mathrm{100}\right)^{\mathrm{4}−\mathrm{k}} \:\left(\mathrm{2}\right)^{\mathrm{k}} \: \\ $$
Commented by gsk2684 last updated on 02/Aug/21
$${thank}\:{u} \\ $$$${i}\:{did}\:{not}\:{remember}\: \\ $$