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2-0-3-0-4-0-e-x-y-z-dx-dy-dz-




Question Number 182242 by mathlove last updated on 06/Dec/22
∫^2 _0 ∫^3 _0 ∫^4 _0 e^(x+y+z)  dx dy dz=?
$$\underset{\mathrm{0}} {\int}^{\mathrm{2}} \underset{\mathrm{0}} {\int}^{\mathrm{3}} \underset{\mathrm{0}} {\int}^{\mathrm{4}} {e}^{{x}+{y}+{z}} \:{dx}\:{dy}\:{dz}=? \\ $$
Answered by Ar Brandon last updated on 06/Dec/22
=(∫_0 ^4 e^x dx)(∫_0 ^3 e^y dy)(∫_0 ^2 e^z dz)
$$=\left(\int_{\mathrm{0}} ^{\mathrm{4}} {e}^{{x}} {dx}\right)\left(\int_{\mathrm{0}} ^{\mathrm{3}} {e}^{\mathrm{y}} {d}\mathrm{y}\right)\left(\int_{\mathrm{0}} ^{\mathrm{2}} {e}^{{z}} {dz}\right) \\ $$

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