2-0-sinx-cosx-dx-2cos-2-x-3sin-2-x- Tinku Tara June 4, 2023 Integration 0 Comments FacebookTweetPin Question Number 17033 by arnabpapu550@gmail.com last updated on 30/Jun/17 ∫Π20sinxcosxdx2cos2x+3sin2x Answered by sma3l2996 last updated on 30/Jun/17 t=sinx⇒dt=cosxdxI=∫10tdt2+t2=12[ln∣2+t2∣]10=12(ln2−ln3)=12ln23 Commented by arnabpapu550@gmail.com last updated on 30/Jun/17 Thankyouverymuch. Terms of Service Privacy Policy Contact: info@tinkutara.com FacebookTweetPin Post navigation Previous Previous post: x-1-x-dx-Next Next post: 0-dx-3-2sinx-cosx- Leave a Reply Cancel replyYour email address will not be published. Required fields are marked *Comment * Name * Save my name, email, and website in this browser for the next time I comment.