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2-2-13-5-5-2-1-3-2-2-13-5-5-2-1-3-1-2-1-1-6-




Question Number 160871 by cortano last updated on 08/Dec/21
  (((2 (((2(√(13))+5)/( (√5)+2)))^(1/3)  +2 (((2(√(13))−5)/( (√5)−2)))^(1/3) +1)^2 −1))^(1/6) =?
$$\:\:\sqrt[{\mathrm{6}}]{\left(\mathrm{2}\:\sqrt[{\mathrm{3}}]{\frac{\mathrm{2}\sqrt{\mathrm{13}}+\mathrm{5}}{\:\sqrt{\mathrm{5}}+\mathrm{2}}}\:+\mathrm{2}\:\sqrt[{\mathrm{3}}]{\frac{\mathrm{2}\sqrt{\mathrm{13}}−\mathrm{5}}{\:\sqrt{\mathrm{5}}−\mathrm{2}}}+\mathrm{1}\right)^{\mathrm{2}} −\mathrm{1}}=? \\ $$
Answered by MJS_new last updated on 08/Dec/21
(±5+2(√(13)))^(1/3) =±(1/2)+((√(13))/2)  (±2+(√5))^(1/3) =±(1/2)+((√5)/2)  ⇒ answer is 2
$$\left(\pm\mathrm{5}+\mathrm{2}\sqrt{\mathrm{13}}\right)^{\mathrm{1}/\mathrm{3}} =\pm\frac{\mathrm{1}}{\mathrm{2}}+\frac{\sqrt{\mathrm{13}}}{\mathrm{2}} \\ $$$$\left(\pm\mathrm{2}+\sqrt{\mathrm{5}}\right)^{\mathrm{1}/\mathrm{3}} =\pm\frac{\mathrm{1}}{\mathrm{2}}+\frac{\sqrt{\mathrm{5}}}{\mathrm{2}} \\ $$$$\Rightarrow\:\mathrm{answer}\:\mathrm{is}\:\mathrm{2} \\ $$

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